-- SELECT with WHERE
SELECT name, email FROM users WHERE active = true;

-- JOIN operations
SELECT u.name, o.total
FROM users u
INNER JOIN orders o ON u.id = o.user_id;

-- Aggregate functions
SELECT category, COUNT(*), AVG(price)
FROM products
GROUP BY category
HAVING COUNT(*) > 5;

-- Subqueries
SELECT * FROM users
WHERE id IN (SELECT user_id FROM orders WHERE total > 1000);

EXPLAIN ANALYZE
SELECT * FROM users WHERE email = 'test@example.com';

-- Look for:
-- - Sequential scans (add indexes)
-- - High cost values
-- - Nested loops on large tables

-- Single column index
CREATE INDEX idx_users_email ON users(email);

-- Multi-column index
CREATE INDEX idx_orders_user_date ON orders(user_id, created_at);

-- Unique index
CREATE UNIQUE INDEX idx_users_username ON users(username);

-- Partial index
CREATE INDEX idx_active_users ON users(email) WHERE active = true;

CREATE TABLE users (
    id SERIAL PRIMARY KEY,
    email VARCHAR(255) UNIQUE NOT NULL,
    name VARCHAR(100) NOT NULL,
    created_at TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
    updated_at TIMESTAMP DEFAULT CURRENT_TIMESTAMP
);

CREATE TABLE orders (
    id SERIAL PRIMARY KEY,
    user_id INTEGER REFERENCES users(id) ON DELETE CASCADE,
    total DECIMAL(10,2) NOT NULL,
    status VARCHAR(50) DEFAULT 'pending',
    created_at TIMESTAMP DEFAULT CURRENT_TIMESTAMP
);

ALTER TABLE users ADD COLUMN phone VARCHAR(20);

-- Add with default
ALTER TABLE users ADD COLUMN verified BOOLEAN DEFAULT false;

ALTER TABLE users ALTER COLUMN email TYPE VARCHAR(320);
ALTER TABLE users ALTER COLUMN name SET NOT NULL;

BEGIN;
    UPDATE accounts SET balance = balance - 100 WHERE id = 1;
    UPDATE accounts SET balance = balance + 100 WHERE id = 2;
COMMIT;

-- With error handling
BEGIN;
    -- operations
    SAVEPOINT sp1;
    -- more operations
    ROLLBACK TO sp1;
COMMIT;

SELECT * FROM products
ORDER BY created_at DESC
LIMIT 20 OFFSET 40;

INSERT INTO users (email, name)
VALUES ('test@example.com', 'Test')
ON CONFLICT (email)
DO UPDATE SET name = EXCLUDED.name;

SELECT
    name,
    salary,
    RANK() OVER (ORDER BY salary DESC) as rank
FROM employees;