Magnetism
Misconceptions
| Misconception | Correction |
|---|---|
| "Magnetic force does work on charged particles" | Magnetic force is always perpendicular to velocity, so it does zero work |
| "Magnetic poles can be isolated" | Magnetic poles always come in north-south pairs; no magnetic monopoles exist |
| "Current flows through a magnetic field to create force" | Force arises from the interaction of moving charges with the magnetic field |
| "Induced EMF depends on the magnetic flux" | Induced EMF depends on the rate of change of flux, not the flux itself |
| "Lenz's law creates energy" | Lenz's law opposes change and is consistent with energy conservation |
Key Concepts
Magnetic Field
A magnetic field B is a vector field that exerts forces on moving charges. Magnetic field lines point from north to south poles outside the magnet and form closed loops.
Units: Tesla (T) = kg/(A·s²) = Wb/m²
Magnetic Force on a Moving Charge
A charge q moving with velocity v in a magnetic field B experiences a force:
F = qvB sin(θ)
Where θ is the angle between v and B.
Key properties:
- •Force is perpendicular to both v and B
- •Force is zero when v is parallel to B
- •Use the right-hand rule: fingers point in v direction, curl toward B, thumb points in F direction (for positive charges)
- •For negative charges, force is opposite to right-hand rule
Magnetic Force on a Current-Carrying Wire
A wire of length L carrying current I in a magnetic field B experiences a force:
F = BIL sin(θ)
Where θ is the angle between the wire and B.
Circular Motion in a Magnetic Field
Since magnetic force is always perpendicular to velocity, a charged particle in a uniform magnetic field moves in a circle (or helix if there's a component parallel to B).
Radius of circular path: r = mv/(qB)
Period: T = 2πm/(qB) (independent of speed!)
Magnetic Field from a Long Straight Wire
A long straight wire carrying current I produces a magnetic field at distance r:
B = μ₀I/(2πr)
Where μ₀ = 4π × 10⁻⁷ T·m/A is the permeability of free space.
Direction: Use right-hand rule - thumb in current direction, fingers curl in direction of B.
Magnetic Field in a Solenoid
A solenoid with n turns per unit length carrying current I produces a uniform field inside:
B = μ₀nI
The field is nearly uniform inside and approximately zero outside.
Faraday's Law of Induction
The induced EMF in a loop equals the negative rate of change of magnetic flux:
EMF = -N × (ΔΦ/Δt)
Where Φ = BA cos(θ) is the magnetic flux, N is the number of turns.
Lenz's Law
The direction of induced current creates a magnetic field that opposes the change in flux that produced it.
Equations
[1] F = qvB sin(θ) (magnetic force on moving charge) [2] F = BIL sin(θ) (force on current-carrying wire) [3] r = mv/(qB) (radius of circular motion) [4] T = 2πm/(qB) (period of circular motion) [5] B = μ₀I/(2πr) (field from long wire) [6] B = μ₀nI (field in solenoid) [7] Φ = BA cos(θ) (magnetic flux) [8] EMF = -N(ΔΦ/Δt) (Faraday's law) [9] μ₀ = 4π × 10⁻⁷ T·m/A (permeability of free space)
Worked Examples
Example 1: Force on a Moving Proton
Problem: A proton (q = 1.6 × 10⁻¹⁹ C) moves at 3 × 10⁶ m/s perpendicular to a 0.5 T magnetic field. What is the magnetic force?
Solution:
- •Use F = qvB sin(θ) with θ = 90°
- •F = (1.6 × 10⁻¹⁹)(3 × 10⁶)(0.5)(1)
- •F = 2.4 × 10⁻¹³ N
Example 2: Circular Motion of an Electron
Problem: An electron (m = 9.11 × 10⁻³¹ kg, q = 1.6 × 10⁻¹⁹ C) moves at 2 × 10⁷ m/s in a 0.01 T field. Find the radius of its circular path.
Solution:
- •Use r = mv/(qB)
- •r = (9.11 × 10⁻³¹)(2 × 10⁷) / [(1.6 × 10⁻¹⁹)(0.01)]
- •r = 1.82 × 10⁻²³ / 1.6 × 10⁻²¹
- •r = 0.0114 m = 1.14 cm
Example 3: Induced EMF
Problem: A 50-turn coil with area 0.02 m² is in a magnetic field that decreases from 0.8 T to 0.2 T in 0.1 s. What is the induced EMF?
Solution:
- •ΔΦ = A × ΔB = 0.02 × (0.2 - 0.8) = -0.012 Wb
- •EMF = -N × ΔΦ/Δt = -50 × (-0.012)/0.1
- •EMF = 6 V
Explanation Patterns
- •Identify the physical situation - Is it force on a charge, force on a wire, or induction?
- •Draw the geometry - Show B field, velocity/current direction, and use right-hand rule
- •Identify the angle - Carefully determine θ between the relevant vectors
- •Apply the appropriate formula - F = qvB, F = BIL, or Faraday's law
- •Check direction using right-hand rule - Especially important for force problems
- •Verify units - Tesla = kg/(A·s²), Weber = T·m²
Common Problem Types
- •Force on moving charges: Calculate force magnitude and direction
- •Circular motion in B field: Find radius, period, or frequency
- •Force on current-carrying wires: Calculate force on straight or curved wires
- •Magnetic field calculations: Find B from wires or solenoids
- •Faraday's law problems: Calculate induced EMF from changing flux
- •Lenz's law: Determine direction of induced current